3.165 \(\int \frac{(f x)^m (a+b \sec ^{-1}(c x))}{(d+e x^2)^2} \, dx\)

Optimal. Leaf size=25 \[ \text{Unintegrable}\left (\frac{(f x)^m \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^2},x\right ) \]

[Out]

Unintegrable[((f*x)^m*(a + b*ArcSec[c*x]))/(d + e*x^2)^2, x]

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Rubi [A]  time = 0.0705689, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int \frac{(f x)^m \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[((f*x)^m*(a + b*ArcSec[c*x]))/(d + e*x^2)^2,x]

[Out]

Defer[Int][((f*x)^m*(a + b*ArcSec[c*x]))/(d + e*x^2)^2, x]

Rubi steps

\begin{align*} \int \frac{(f x)^m \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^2} \, dx &=\int \frac{(f x)^m \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^2} \, dx\\ \end{align*}

Mathematica [A]  time = 1.91642, size = 0, normalized size = 0. \[ \int \frac{(f x)^m \left (a+b \sec ^{-1}(c x)\right )}{\left (d+e x^2\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[((f*x)^m*(a + b*ArcSec[c*x]))/(d + e*x^2)^2,x]

[Out]

Integrate[((f*x)^m*(a + b*ArcSec[c*x]))/(d + e*x^2)^2, x]

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Maple [A]  time = 1.95, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( fx \right ) ^{m} \left ( a+b{\rm arcsec} \left (cx\right ) \right ) }{ \left ( e{x}^{2}+d \right ) ^{2}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f*x)^m*(a+b*arcsec(c*x))/(e*x^2+d)^2,x)

[Out]

int((f*x)^m*(a+b*arcsec(c*x))/(e*x^2+d)^2,x)

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Maxima [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arcsec}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (e x^{2} + d\right )}^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(a+b*arcsec(c*x))/(e*x^2+d)^2,x, algorithm="maxima")

[Out]

integrate((b*arcsec(c*x) + a)*(f*x)^m/(e*x^2 + d)^2, x)

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Fricas [A]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b \operatorname{arcsec}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{e^{2} x^{4} + 2 \, d e x^{2} + d^{2}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(a+b*arcsec(c*x))/(e*x^2+d)^2,x, algorithm="fricas")

[Out]

integral((b*arcsec(c*x) + a)*(f*x)^m/(e^2*x^4 + 2*d*e*x^2 + d^2), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)**m*(a+b*asec(c*x))/(e*x**2+d)**2,x)

[Out]

Timed out

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Giac [A]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{arcsec}\left (c x\right ) + a\right )} \left (f x\right )^{m}}{{\left (e x^{2} + d\right )}^{2}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x)^m*(a+b*arcsec(c*x))/(e*x^2+d)^2,x, algorithm="giac")

[Out]

integrate((b*arcsec(c*x) + a)*(f*x)^m/(e*x^2 + d)^2, x)